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Home » Your Java Primer Data Type Guide Just Got Faster—Check Out This Bits-Bytes Table! - DevRocket

Your Java Primer Data Type Guide Just Got Faster—Check Out This Bits-Bytes Table! - DevRocket

📅 May 3, 2026 👤 scraface

May 03, 2026

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ight)^2 = (55)^2 = 3025.
Now compute $3025 \mod 9$. Use the digit sum method:
Digit sum of $3025$: $3 + 0 + 2 + 5 = 10$, then $1 + 0 = 1$, so $3025...
Alternatively, divide: $3025 \div 9 = 336 imes 9 = 3024$, remainder $...
Thus, the remainder is $1$.
Therefore, the answer is $oxed{1}$.
Question: What is the greatest common divisor of $3^{15} - 1$ and $3^9...
Solution: Use the property:
\gcd(a^m - 1, a^n - 1) = a^{\gcd(m,n)} - 1, \quad ext{for } a > 1.
\gcd(3^{15} - 1, 3^9 - 1) = 3^{\gcd(15,9)} - 1.

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