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what is purchasing power parity - DevRocket

📅 May 3, 2026 👤 scraface

May 03, 2026

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z^2 = -2 \Rightarrow z = \pm \sqrt{-2} = \pm i\sqrt{2}
So the solutions are \( z = i\sqrt{2} \) and \( z = -i\sqrt{2} \). Eac...
But wait — \( z^2 = -2 \) has exactly two solutions in \( \mathbb{C} \...
z = \sqrt{2}i, \quad z = -\sqrt{2}i
These are distinct and purely imaginary. The real part of each is 0.
Thus, the sum of the real parts is:
+ 0 = 0
Even though there are four roots? Let's double-check factorization.
Go back:
z^4 + 4z^2 + 4 = (z^2 + 2)^2 = 0

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