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📰 Wait—perhaps the problem allows degree ≤ 3. Many contest problems phrase cubic loosely. Given the values fit a quadratic, and no higher-degree terms are forced, the minimal-degree interpolating polynomial is quadratic. Since the problem asks to find $ p(0) $, and the unique cubic polynomial (in degree ≤ 3) satisfying the values must have $ a = 0 $, we proceed with $ p(x) = 2x^2 + x $, so $ p(0) = 0 $. However, to ensure degree 3, suppose we include a zero cubic term. Then $ p(x) = 0x^3 + 2x^2 + x + 0 $, and $ p(0) = 0 $. 📰 But let's verify all values: 📰 $ p(1) = 2 + 1 = 3 $, 📰 Columbus Data Exposed The Secret Strategy Behind His Legendary Data Mastery 9042759 📰 Break Free Before Its Too Lateomnilife Redefines Everything You Thought Was Possible 2392824 📰 You Wont Believe The Hidden Secrets Of Strawberry Shortcakes 2009 Characters 6719454 📰 Microsoft Surface Apps That Will Change How You Work Forever Dergies Inside 7634149 📰 Transamerica Building 9177532 📰 How A Simple Website Game Changed Online Gaming Foreverdont Miss Out 8276306 📰 Well Fargo Mortgage 5511443 📰 This Simple Tune Will Make Your Guitar Sound Like A Pro Open G Tuning Revealed 7026068 📰 Decompensated Heart Failure 1585253 📰 Cast Landman 4153251 📰 Golden Bachelor 2025 9889915 📰 The Full Story Ages Of Conflict That Shaped Civilizations Darkest Era 6336358 📰 5Psvr2 Games That Will Transform Your Vr Experiencedlc Or Masterpieces 537199 📰 Amazon Sale Amazon Sale 7007186 📰 A Ladder Leans Against A Wall Forming A Right Triangle With The Ground The Ladder Is 13 Meters Long And Reaches 12 Meters Up The Wall How Far Is The Base Of The Ladder From The Wall 3367203